Study sheet: Moving Charges and Magnetism

Course Outline

  1. Magnetic Force and Particle Motion
  2. Forces on Current-Carrying Conductors
  3. Magnetic Fields from Currents
  4. Loops, Solenoids, and Ampere Law
  5. Galvanometer and Its Conversions

1. Magnetic Force and Particle Motion

Essential Points

๐Ÿ“ Formula โ€” The magnetic force on a charged particle is F=qvBsinโกฮธF=qvB\sin\theta, where ฮธ is the angle between velocity and magnetic field.

๐Ÿ“ Formula โ€” In a uniform magnetic field, magnetic force supplies the centripetal force according to qvB=mv2rqvB=\frac{mv^2}{r}.

๐Ÿ“ Formula โ€” The radius, time period, and frequency of a charged particle moving in a circular path are r=mvqBr=\frac{mv}{qB}, T=2ฯ€mqBT=\frac{2\pi m}{qB}, and f=qB2ฯ€mf=\frac{qB}{2\pi m}, respectively.

  • When the velocity is perpendicular to the magnetic field, the magnetic force is F=qvBF=qvB and is perpendicular to both the velocity and the magnetic field.

Memory Hook

Magnetic force โŸ‚ velocity โ†’ circular motion

2. Forces on Current-Carrying Conductors

โ˜… Must-know

๐Ÿ“ Formula โ€” The force on a straight current-carrying conductor in a magnetic field is F=BIlsinโกฮธF=BIl\sin\theta.

๐Ÿ“ Formula โ€” The force per unit length between two parallel current-carrying conductors separated by distance d is Fl=ฮผ0I1I22ฯ€d\frac{F}{l}=\frac{\mu_0 I_1I_2}{2\pi d}.

๐Ÿ“Œ Parallel currents flowing in the same direction attract each other, whereas parallel currents flowing in opposite directions repel each other.

Further detail

๐Ÿ“ Formula โ€” For a conductor perpendicular to the magnetic field, the force is F=BIlF=BIl.

Memory Hook

Same-direction currents attract; opposite-direction currents repel

3. Magnetic Fields from Currents

โ˜… Must-know

๐Ÿ“ Formula โ€” The magnetic field due to a long straight current-carrying conductor is B=ฮผ0I2ฯ€rB=\frac{\mu_0I}{2\pi r}.

๐Ÿ“ Formula โ€” For a circular coil of N turns, area A, and current I in a magnetic field B, the torque is ฯ„=NIABsinโกฮธ\tau=NIAB\sin\theta.

๐Ÿ“ Formula โ€” The magnetic dipole moment of a coil is M=NIAM=NIA.

Further detail

๐Ÿ“ Formula โ€” Biotโ€“Savart law gives the field contribution dB=ฮผ04ฯ€Iโ€‰dlsinโกฮธr2dB=\frac{\mu_0}{4\pi}\frac{I\,dl\sin\theta}{r^2} from a current element.

4. Loops, Solenoids, and Ampere Law

โ˜… Must-know

๐Ÿ“ Formula โ€” The magnetic field at the centre of a circular loop with N turns and radius R is B=ฮผ0NI2RB=\frac{\mu_0NI}{2R}.

๐Ÿ“ Formula โ€” Ampereโ€™s circuital law states that the line integral of magnetic field around a closed path is โˆฎBโ‹…dl=ฮผ0I\oint\mathbf{B}\cdot d\mathbf{l}=\mu_0I.

๐Ÿ“ Formula โ€” For a long solenoid with n turns per unit length, the magnetic field inside is B=ฮผ0nIB=\mu_0nI, or B=ฮผ0NIlB=\frac{\mu_0NI}{l} when n=N/l.

Further detail

  • For a long solenoid, the field outside is approximately zero, and the number of turns in a length l is nl.

Memory Hook

Loop โ†’ solenoid โ†’ enclosed current

5. Galvanometer and Its Conversions

โ˜… Must-know

๐Ÿ“ Formula โ€” For a moving-coil galvanometer at equilibrium, magnetic torque equals restoring torque: NIAB=kฮธNIAB=k\theta.

๐Ÿ“ Formula โ€” The current sensitivity of a galvanometer is ฮธI=NBAk\frac{\theta}{I}=\frac{NBA}{k}.

๐Ÿ“ Formula โ€” To convert a galvanometer of resistance G and maximum current I_g into an ammeter of range I, the parallel shunt resistance is S=IgGIโˆ’IgS=\frac{I_gG}{I-I_g}.

๐Ÿ“ Formula โ€” To convert a galvanometer into a voltmeter of range V, the required series resistance is R=VIgโˆ’GR=\frac{V}{I_g}-G.

Further detail

๐Ÿ“Œ A low-resistance shunt is connected in parallel with the galvanometer to form an ammeter, whereas a high resistance is connected in series with the galvanometer to form a voltmeter.

Memory Hook

Ammeter: low parallel shunt; voltmeter: high series resistance

Synthesis Tables

Galvanometer Conversions

InstrumentAdded resistanceConnectionRelation
AmmeterLow-resistance shunt SParallelS=IgGIโˆ’IgS=\frac{I_gG}{I-I_g}
VoltmeterHigh resistance RSeriesR=VIgโˆ’GR=\frac{V}{I_g}-G

Test your knowledge

Test your knowledge on Moving Charges and Magnetism with 9 multiple-choice questions with detailed corrections.

1. A charged particle moves at an angle of 90โˆ˜90^\circ to a uniform magnetic field. Which expression gives the magnetic force on the particle?

2. A charged particle moves through a uniform magnetic field with its velocity perpendicular to the field. Which equation describes the role of the magnetic force in its circular motion?

Take the quiz โ†’

Review with flashcards

Memorize the key concepts of Moving Charges and Magnetism with 10 interactive flashcards.

What is the formula for magnetic force on a charged particle?

F=qvBsinโกฮธF=qvB\sin\theta where ฮธ\theta is the angle between velocity and magnetic field.

What is the radius formula for a charged particle in circular motion in a magnetic field?

r=mvqBr=\frac{mv}{qB}

What is the formula for force on a straight current-carrying conductor in a magnetic field?

F=BIlsinโกฮธF=BIl\sin\theta

See flashcards โ†’

Similar courses

Create your own study sheets

Import your course and AI generates sheets, quizzes and flashcards in 30 seconds.

Sheet generator