1. What is an infinite sequence?
An ordered list of numbers indexed by integers
Spiegazione
An infinite sequence is an ordered list of numbers, commonly indexed by the positive integers. A series, by contrast, is formed from sums of terms.
An ordered list of numbers indexed by integers
Spiegazione
An infinite sequence is an ordered list of numbers, commonly indexed by the positive integers. A series, by contrast, is formed from sums of terms.
Its terms approach a finite number as the index grows
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A sequence converges when its terms become arbitrarily close to a finite limit as the index approaches infinity. If no finite limit exists, the sequence diverges.
For -1 < r ≤ 1
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The sequence r^n converges precisely when -1 < r ≤ 1. Its limit is 0 for -1 < r < 1 and 1 when r = 1.
It converges
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Every bounded monotonic sequence converges. In particular, a decreasing sequence bounded below has a finite limit.
The sequence of its partial sums approaches a finite real number
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An infinite series converges when the sequence of its partial sums approaches a finite real number. The terms themselves need not become exactly zero.
s_n = Σ from i=1 to n of a_i
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The nth partial sum is the finite sum s_n = Σ from i=1 to n of a_i. The infinite series is interpreted through the limit of these partial sums.
a/(1 − r)
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A geometric series with first term a and common ratio r converges for |r| < 1, and its sum is a/(1 − r).
The series diverges
Spiegazione
If the terms of a series do not approach zero, the series diverges. When the terms do approach zero, the term test alone is inconclusive.
f is continuous, positive, and decreasing on the relevant tail, with a_n = f(n)
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The Integral Test requires f to be continuous, positive, and decreasing on the relevant tail. Under these conditions, the series and the improper integral have the same convergence behavior.
p > 1
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The p-series converges exactly when p > 1. The boundary case p = 1 is the harmonic series and diverges.
∫ from n+1 to infinity of f(x) dx ≤ R_n ≤ ∫ from n to infinity of f(x) dx
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The integral remainder estimate places R_n between the integrals from n+1 and n to infinity. The lower bound uses the later starting point, while the upper bound uses n.
It converges
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A nonnegative series bounded term by term above by a convergent series must also converge. The comparison provides an upper bound on its partial sums.
The two series either both converge or both diverge
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A positive finite ratio limit means the terms have comparable asymptotic size, so the two positive-term series share the same convergence behavior. A zero or infinite limit would not justify this conclusion.
The terms b_n decrease and approach zero
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The alternating series test requires decreasing magnitudes b_n that tend to zero. Alternating signs alone do not guarantee convergence.
|R_n| ≤ b_{n+1}
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The alternating-series remainder is no larger in magnitude than the first omitted term, which is b_{n+1}. This bound depends on the alternating-series conditions.
Absolute convergence means ∑|a_n| converges, while conditional convergence means ∑a_n converges but ∑|a_n| diverges
Spiegazione
Absolute convergence occurs when the series of absolute values converges. Conditional convergence occurs when the original signed series converges but its absolute-value series diverges.
The series diverges immediately
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A necessary condition for convergence is that a_n approaches zero. If the term limit is nonzero or does not exist, the series diverges; a zero limit merely permits further testing.
The Ratio Test
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The supplied method-selection guidance recommends the Ratio Test for factorials and products. It separately associates the Root Test with terms of the form (b_n)^n.
For \(|x|<1\)
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The geometric identity converges when \(|x|<1\). Any endpoint must be checked separately after substitution because the identity does not automatically include \(|x|=1\).
The convergence condition
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Substitution changes both the terms of the series and the condition under which the resulting series converges. Changing only the terms gives an incomplete representation.
By differentiating each term to get \(\sum_{n=1}^{\infty}nc_n(x-a)^{n-1}\)
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Within the radius of convergence, term-by-term differentiation is valid and produces \(\sum_{n=1}^{\infty}nc_n(x-a)^{n-1}\).
\(f^{(n)}(a)/n!\)
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The coefficient of \((x-a)^n\) is \(c_n=f^{(n)}(a)/n!\). Derivatives evaluated at 0 specifically produce Maclaurin coefficients.
\(\sum_{i=0}^{n}\frac{f^{(i)}(a)}{i!}(x-a)^i\)
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The nth Taylor polynomial is finite and includes terms from \(i=0\) through \(i=n\). The infinite version represents the Taylor series rather than the polynomial.
When the remainder approaches zero on the interval
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A Taylor series equals the function only if the remainder \(R_n(x)=f(x)-T_n(x)\) approaches zero on the interval being considered.
\(|R_n(x)|\leq \frac{M|x-a|^{n+1}}{(n+1)!}\)
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Taylor’s Inequality bounds the remainder by \(M|x-a|^{n+1}/(n+1)!\) under the stated derivative bound.
Infinity
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The series \(e^x=\sum_{n=0}^{\infty}x^n/n!\) converges for every x, so its radius of convergence is infinite.
Sine uses odd powers, while cosine uses even powers
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The sine series contains powers \(x^{2n+1}\), which are odd, while the cosine series contains powers \(x^{2n}\), which are even. Both have infinite radius of convergence.
Choose a, compute derivatives through order n, construct T_n, and bound the next derivative over the interval
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Constructing T_n requires selecting the center, evaluating derivatives through order n, forming the polynomial, and bounding the next derivative over the entire interval. The approximation is local to the chosen center, so error control requires attention to the interval.
Apply Taylor's Inequality using the derivative bound
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Taylor's Inequality estimates the remainder when a suitable bound on a derivative is known over the interval. Evaluating only at the center does not measure the approximation error away from that point.
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What is an infinite sequence in mathematics?
An ordered list of numbers indexed by positive integers or another integer set.
When does a sequence converge to a limit L?
When its terms become arbitrarily close to L as n approaches infinity.
What happens if a sequence has no finite limit?
The sequence diverges.
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