Series with Arbitrary Signs Flashcards (29 cards)

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1Question

How are the terms of a real alternating series expressed using a positive sequence?

Answer

un=(−1)nanu_n=(-1)^n a_n or un=(−1)n+1anu_n=(-1)^{n+1}a_n, where an=∣un∣>0a_n=|u_n|>0.

2Question

What conditions ensure convergence under the Alternating Series Test for un=(−1)nanu_n=(-1)^n a_n?

Answer

an≥0a_n\geq 0 is eventually decreasing and tends to zero.

3Question

When does the alternating Riemann series converge?

Answer

It converges if and only if α>0\alpha>0.

4Question

When is a numerical series ∑un\sum u_n absolutely convergent?

Answer

When ∑∣un∣\sum |u_n| converges.

5Question

What does convergence of ∑∣un∣\sum |u_n| imply about ∑un\sum u_n?

Answer

∑un\sum u_n converges.

6Question

What bound holds when ∑∣un∣\sum |u_n| converges?

Answer

∣∑n=0∞un∣≤∑n=0∞∣un∣\left|\sum_{n=0}^{\infty}u_n\right|\leq\sum_{n=0}^{\infty}|u_n|.

7Question

What does conditional convergence mean for a series and its absolute-value series?

Answer

The series converges, but its series of absolute values diverges.

8Question

What should be checked first when determining the nature of an arbitrary-sign series?

Answer

Check whether un→0u_n\to0.

9Question

After confirming un→0u_n\to0, what series should be tested?

Answer

Test the absolute-value series ∑∣un∣\sum|u_n|.

10Question

If the absolute-value series diverges, what tests or methods follow?

Answer

Check the Alternating Series Test; otherwise use an asymptotic expansion of the general term.

11Question

How do consecutive term signs behave in an alternating series?

Answer

Consecutive terms have opposite signs.

12Question

How is the remainder magnitude bounded for a convergent alternating series?

Answer

∣Rn∣≤an+1=∣un+1∣|R_n|\leq a_{n+1}=|u_{n+1}|.

13Question

What determines the sign of the remainder in a convergent alternating series?

Answer

It has the same sign as the first omitted term, un+1u_{n+1}.

14Question

Between which partial sums does the sum of a convergent alternating series lie?

Answer

S2n+1≤S≤S2nS_{2n+1}\leq S\leq S_{2n}.

15Question

Why does ∑n(−1)nn+1\sum_{n}\frac{(-1)^n}{n+1} converge by the Alternating Series Test?

Answer

Its magnitudes 1n+1\frac{1}{n+1} decrease to zero.

16Question

When does the standard Riemann series converge?

Answer

It converges if and only if α>1\alpha>1.

17Question

Why does the alternating Riemann series diverge when α≤0\alpha\leq0?

Answer

Its terms do not tend to zero.

18Question

What series should be tested for absolute convergence with arbitrary signs?

Answer

The positive-term series ∑∣un∣\sum |u_n|.

19Question

Which tests can establish convergence of ∑∣un∣\sum |u_n|?

Answer

Positive-series tests such as the Riemann, comparison, ratio, or root test.

20Question

Why does ∑n≥1cos⁡nn2\sum_{n\geq1}\frac{\cos n}{n^2} converge absolutely?

Answer

Its absolute terms are bounded by 1/n21/n^2, whose series converges.

21Question

What does the absolute-term ratio tend to for un=(−1)nn3n!u_n=\frac{(-1)^n n^3}{n!}?

Answer

Zero.

22Question

Why does ∑n≥0(−1)nn3n!\sum_{n\geq0}\frac{(-1)^n n^3}{n!} converge absolutely?

Answer

Its absolute-value series converges by the Ratio Test.

23Question

Why is the alternating harmonic series conditionally convergent?

Answer

It converges, while the harmonic series of absolute values diverges.

24Question

Which test establishes convergence of the alternating harmonic series?

Answer

The Alternating Series Test.

25Question

Why is ∑n≥1(−1)n/n\sum_{n\geq1}(-1)^n/\sqrt n conditionally convergent?

Answer

It converges, while ∑n≥11/n\sum_{n\geq1}1/\sqrt n diverges.

26Question

Which test establishes convergence of ∑n≥1(−1)n/n\sum_{n\geq1}(-1)^n/\sqrt n?

Answer

The Alternating Series Test.

27Question

For un=(−1)n(n+1−n)u_n=(-1)^n(\sqrt{n+1}-\sqrt n), what does rationalization give for ∣un∣|u_n|?

Answer

∣un∣=1n+1+n∼12n|u_n|=\frac{1}{\sqrt{n+1}+\sqrt n}\sim\frac{1}{2\sqrt n}.

28Question

For un=(−1)n(n+1−n)u_n=(-1)^n(\sqrt{n+1}-\sqrt n), what is the convergence status of its absolute-value series?

Answer

It diverges.

29Question

For un=(−1)n(n+1−n)u_n=(-1)^n(\sqrt{n+1}-\sqrt n), what is the convergence status of the series?

Answer

It is conditionally convergent.

Test yourself with the quiz

Answer 12 questions on Series with Arbitrary Signs.

1. For the sequence un=(−1)n(n+2)n+1u_n=\frac{(-1)^n(n+2)}{n+1}, which sequence gives the magnitudes in its alternating-series representation?

2. A real sequence has terms u0=5u_0=5, u1=−3u_1=-3, and u2=2u_2=2. What sign must u3u_3 have if the sequence is alternating?

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Go over the full study guide for Series with Arbitrary Signs.

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